Percentage MCQ Test 2

1. Balanced diet should contain 12% of proteins, 25% of fats and 63% of carbohydrates. If a child needs 2600 calories in this food daily, find in calories the amount of carbohydrates in his daily food intake.

A) 1600
B) 1638
C) 1666
D) 1696

ANSWER=> (B)
Explanation/Answer:-
a balanced diet contains 63% carbohydrates.
∴ Amount of carbohydrates in food intake = 63% of 2600=63100×2600=1638

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2. A cricketer scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and 8 singles. What percentage of the total runs came in singles?

A) 12.90%
B) 13.90%
C) 14.90%
D) 15.90%

ANSWER=> (A)
The cricketer hits 8 singles.i.e., 8×1=8∴ 862×100=12.90%

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3. 72% of 25 students are good in Mathematics. How many are not good in Mathematics?

A) 8
B) 7
C) 6
D) 5

ANSWER=> (B)
Explanation/Answer:- (100-72)% =28% Not good in mathemetics.
∴ 28% of 25=28/100*25=7

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4. If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?

A) 5:3
B) 2:5
C) 3:5
D) 4:5

ANSWER=> (A)
Explanation/Answer:- 40% of x = 2/3 of y => 2/5*x= 2/3*y=>5/3

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5. Two fifth of one third of three seventh of a number is 15. What is 40 percent of that number?

A) 72
B) 84
C) 105
D) 120

ANSWER=> (C)
Explanation/Answer:- 2/5*1/3*3/7*X=15 => X=(15*5*3*7)/(2*3)
40% of X =40/100*(15*5*3*7)/(2*3)=105

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6. If A is 25% of B then what % is B of A?

A) 40
B) 400
C) 120
D) 150

ANSWER=> (B)
Explanation/Answer:- LET B IS 100 SO A=25
% is B of A=100/25*10=400

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7. Let x and y be two numbers such that x = 5y. Then y is less than x by:

A) 50%
B) 60%
C) 70%
D) 80%

ANSWER=> (D)
Explanation/Answer:- X=5Y=> So Y/X=1/5
Y is less than x by=x-y/x*100 => (1-y/x)*100 => (1-1/5)*100 => 4/5*100=80%

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8. The numerator of a fraction is increased by 20% and its denominator be diminished by 10%. The value of new fraction is , then the fraction is:

A) 4/3
B) 3/2
C) 3/8
D) 9/4

ANSWER= (A)
Explanation/Answer:- (100+20)/(100-10) = 120/90 = 4/3

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9. The price of sugar rises by 50%. By what percent family reduces the consumption of sugar, so that the expenditure does not increase?

A) 30%
B) 60%
C) 90%
D) 120%

ANSWER= (B)
Explanation/Answer:- Let the Initial price of sugar = 100 per kg
Now the price of sugar = 150 per kg
Initially family was conusming 100 Rs. for 1 kg of sugar.
Sugar quantity with new rate 150 Rs. per kg for 100 Rs. = 100/150 = 2/5 kg (0.4 kg)
Percentage of consumption should reduce by = (1-0.4)/100
= 0.6/100
= 60%

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10. 30 % of a number is 10 less than two-third of that number. Find the number?

A) 500/100
B) 250/7
C) -250/7
D) 20/3

ANSWER= (C)
Explanation/Answer:- x*(2/3) - 30% of x = 10 => x*(2/3) - (30/100) * x =10
x(2/3 - 30/100) =10
x(-84/300) = 100
x = 10*300/-84
=3000/-84
=-250/7